Hi,
D is the correct answer. The highest product of the 3 scores one can get if one rolls 3 dice is

. List all the perfect squares less than 216. These are:
1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196
So let's consider them individually.
1 - we could have a 1 on the first die, 1 on the second die and 1 on the last die. I'll write it as (1, 1, 1) -
1 option only
4 - (1,2,2), (2,1,2), (2,2,1) or (4,1,1), (1,4,1), (1,1,4) -
6 options
9 - (3,3,1),(3,1,3), (1,3,3) -
3 options
I'll use a bit of combinatorics theory here - It's not that hard!
16 - Arrange 3 numbers in a row (4,2,2) of which 2 are identical

. Also arrange 3 numbers in a row (4,4,1) of which 2 are identical

-
6 options in total
25 - (5,5,1) Arrange 3 numbers in a row (5,5,1) of which 2 are identical

-
3 options
36- (6,6,1) arrange 3 numbers in a row of which 2 are identical

. (4,3,3). Arrange 3 numbers in a row of which 2 are identical

. Arrange (2,3,6) in a row

-
12 options in total
49 - No combinations (product of 2 primes, each prime is greater than 6.
64- (4,4,4) -
1 option only
81 - No combinations since factor 9 is greater than 6.
100 - (5,5,4) arrange 3 numbers in a row of which 2 are identical

.
3 options
144 - (6,6,4) arrange 3 numbers in a row of which 2 are identical

.
3 options
Total number of options
The probability that the product of the 3 scores is a perfect square is
What a nice little question.